ABCD is a cyclic trapezium with AB parallel to CD. If angle B = 45° then find other 3 angles of trapezium .
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Answer:
Given- ABCD is a trapezium with AB∥CD, ∠A=∠B=45°
To find out- ∠D and ∠C=?
Solution-
∠A and ∠D are the adjacent angles of the trapezium within AB∥CD.
∴∠A+∠D=180°
⇒45 °
+∠D=180 °
⇒∠D=135°
Similarly ∠B and ∠C are the adjacent angles of the trapezium within AB∥CD.
∴∠B+∠C=180°
⇒45 °
+∠C=180 °
∠C=135 °
Step-by-step explanation:
Hope it was helpful
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