ABCD is a cyclic trapezium with AD || BC. If angle B=70, determine other three angles
of the trapezium.
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Answer:
GIVEN ABCD IS CYCLIC
where AD ll BC
and angle B =70°
TO FIND
ANGLE A,C&D
angle A = 180-B (co-interior)
A= 180°-70°= 110°
angle C = 180°-A ( opposite angles of a cyclic quadrilateral are supplementary ).
C = 180° - 110°
= 70°
angle D = 180°-B ( opposite angles of a cyclic quadrilateral are supplementary ).
D= 180° -70°
= 110°
Therefore A = 110°
C = 70°
D = 110°
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