ABCD is a cyclic trapezium with AD||BC. If ∠B=70°, determine other three angles of the trapezium.
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Answer:
B=70
C=70
A=x
D=x
- x+70+x+70=360
- 2x+140=360
- 2x=360-140
- 2x=220
- x=220÷2
- x=110
A=110
B=70
C=70
D=110
110+70+70+110=360
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