Question

ABCD is a kite and Angle A equal to angle C if angle CAD equal to 70 degree angle CBD equal to 65 degree find angle BCD and angle ADC​

Answer 1

Step-by-step explanation:

It is given that ABCD is a kite in which ∠CAD=70°, ∠CBD=65° and ∠A=∠C.

Now, in ΔACD, we have

∠A+∠C+∠D=180° (Angle sum property)

⇒∠CAD+∠ADC+∠ACD=180°

⇒70°+70°+∠ADC=180°

⇒∠ADC=40°

Now, From ABCD, we have

∠A+∠B+∠C+∠D=360° (Sum of all the angles of quadrilateral is 360°)

⇒∠BAD+∠ABC+∠BCD+∠CDA=360°

⇒2(∠CAD)+2(∠CBD)+∠BCD+∠CDA=360°

⇒2(70)+2(65)+∠BCD+40=360°

⇒∠BCD=50°

brainliest please.....................................

Answer 2

Answer:

BCD=65 degree

ADC=70 degree

Step-by-step explanation:

A and C is same means 30 because D was left means 10,now add all 30+30+10=70 than it is clear A and C is 30 than B is 25 because as we know C=30 and D=10 now add it 10+30=40+25=65 than in 65 subtract 25,65-25=40 so it is also clear that B is 25