ABCD is a kite angle A= angle C. If angle CAD= 70degree angle CBD=65degree, find angle BCD and angle ADC
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pls see the pic, there's you're answer
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Answered by
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Answer:
Step-by-step explanation:
It is given that ABCD is a kite in which ∠CAD=70°, ∠CBD=65° and ∠A=∠C.
Now, in ΔACD, we have
∠A+∠C+∠D=180° (Angle sum property)
⇒∠CAD+∠ADC+∠ACD=180°
⇒70°+70°+∠ADC=180°
⇒∠ADC=40°
Now, From ABCD, we have
∠A+∠B+∠C+∠D=360° (Sum of all the angles of quadrilateral is 360°)
⇒∠BAD+∠ABC+∠BCD+∠CDA=360°
⇒2(∠CAD)+2(∠CBD)+∠BCD+∠CDA=360°
⇒2(70)+2(65)+∠BCD+40=360°
⇒∠BCD=50°
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