Math, asked by grishma21, 7 months ago

. ABCD is a kite in which AB = AD and
BC = DC. M, N and O are mid-points of sides
AB, BC and CD. Prove that
(i) ZMNO = 90°
(ii) The line MP drawn parallel to NO
bisects AD
A​

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Answered by ruchikuls2502
3

Answer:

ABCD is a . ABCD is a kite in which AB = AD and

. ABCD is a kite in which AB = AD andBC = DC. M, N and O are mid-points of sides

. ABCD is a kite in which AB = AD andBC = DC. M, N and O are mid-points of sidesAB, BC and CD. Prove that

. ABCD is a kite in which AB = AD andBC = DC. M, N and O are mid-points of sidesAB, BC and CD. Prove that(i) ZMNO = 90°

. ABCD is a kite in which AB = AD andBC = DC. M, N and O are mid-points of sidesAB, BC and CD. Prove that(i) ZMNO = 90°(ii) The line MP drawn parallel to NO

. ABCD is a kite in which AB = AD andBC = DC. M, N and O are mid-points of sidesAB, BC and CD. Prove that(i) ZMNO = 90°(ii) The line MP drawn parallel to NObisects AD

. ABCD is a kite in which AB = AD andBC = DC. M, N and O are mid-points of sidesAB, BC and CD. Prove that(i) ZMNO = 90°(ii) The line MP drawn parallel to NObisects ADA

Answered by kharwarsuraj030
0

Answer:

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