Question

ABCD is a kite in which angle BDC =35 BAC= 25 Find BAC,BCD,ABC. ​

Answer 1

Answer:

Given,

∠BAD=70

∠ABD=56

∠ADC=72

ABCD is a cyclic quadrilateral.We know, that sum of opposite angles of a cyclic quadrilateral is 180.

Therefore,

∠BAD+∠BCD=180

=>∠BCD=180−70

=110 (ii)

∠ADC+∠ABC=180

=>72+∠ABD+∠DBC=180

=>72+56+∠CBD=180

=>∠CBD=180−128

=52

In △BCD,

∠BCD+∠DBC+∠BDC=180

=>110+52+∠BDC=180

=>∠BDC=18 (i)

Step-by-step explanation:

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