abcd is a parallegrm AP bisects angle A and CQ bisects angle C P lies on CD and Q lies on AB AP is parallel CQ
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Given that : ABCD is a parallelogram.
AP and CQ are bisector of angle A and C respectively.
Since opposite angles are equal in a parallelogram.
Therefore, ∠A = ∠C
1/2∠A = 1/2∠C
∠1 = ∠2
Now, ABIICD and the transversal CQ intersects them.
∠2 = ∠3 .
from these we get
∠1= ∠3
Thus, transversal AB intersects AP and CQ at A and Q such that ∠1= ∠3 i.e. corresponding angles are equal.
AP II CQ
AP and CQ are bisector of angle A and C respectively.
Since opposite angles are equal in a parallelogram.
Therefore, ∠A = ∠C
1/2∠A = 1/2∠C
∠1 = ∠2
Now, ABIICD and the transversal CQ intersects them.
∠2 = ∠3 .
from these we get
∠1= ∠3
Thus, transversal AB intersects AP and CQ at A and Q such that ∠1= ∠3 i.e. corresponding angles are equal.
AP II CQ
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Answer:
Draw ABCD parallelogram and bisect angle A and C, and join lines AP and QC. Prove as described.
Step-by-step explanation:
Given ABCD is a parallelogram.
As opposite angles are equal in a parallelogram;
∠A = ∠C
Again given, AP and CQ are bisector of angle A and C, respectively.
1/2∠A = 1/2∠C
∠APD = ∠QCD
Hence, AP II CQ (as corresponding angles are equal)
Also, in AQCP
As, AB II DC, so AQ II PC.
Also, AP II CQ.
So, AQCP is a parallelogram (proved)
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