ABCD is a parallellogram havind adjacent side AB -35 CM AND BC-28cm if the distance between its longer sides is 8 cm , find- Area of parallelogram The distance between its shorter side
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adjacent sides=35cm,28cm
distance between longer side=8cm
then,
1/2*(35+35)*4=280cm sq.
distance between shorter sides will be,
1/2*(28+28)*h =280cm sq.
=280/20
=10cm
distance between longer side=8cm
then,
1/2*(35+35)*4=280cm sq.
distance between shorter sides will be,
1/2*(28+28)*h =280cm sq.
=280/20
=10cm
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