Question

ABCD is a parallelogram. A is joined to any point E on BC. AE and DC produced meet at F. Prove that area of triangle BEF = area of triangle CDE.

Answer 1

Answer:

2AB

Step-by-step explanation:

△DCE and BFE

any DEC = any BEF (vertically opp any)

EC=BE (E is the mid point)

∠DCB=∠EBF (alternate angle DC parallel to AF)

So △DCE congruent to △BFE

Therefore DC=BF ...(1)

now CD = AB (ABCD is a parallelogram)

soAF=AB+BF

=AB+DC from (1)

=AB+AB

=2AB