ABCD is a parallelogram, AB=20, BC=25, AE| CD, AF|BC and AE= 7.5 Find the length of AF
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In △AFE and △BFC,
∠AFE=∠BFC (Common angle)
∠AEF=∠BCF (Corresponding angles of parallel lines)
∠FAE=∠CBF (Corresponding angles of parallel lines)
Thus, △AFE∼△CFB (AAA rule)
Hence,
BF
AF
=
BC
AE
AF+AB
AF
=
BC
AE
8+12
8
=
BC
4
BC=
8
4×20
BC=10 cm
Perimeter of parallelogram = AB+BC+BC+AD
Perimeter of parallelogram = 2(AB+BC)
Perimeter of parallelogram = 2(12+10) (Opposite sides are equal)
Perimeter of parallelogram = 44 cm
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