ABCD is a parallelogram , AB = 5 cm , BC = 4 cm , then the value of AC^2 + BD^2 is
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Answer:
AC =3,BD=3.
AC^2+BD^2=18
18 is the answer
Answered by
0
Answer:
By pythagoras theorom,
bc^2= ab^2+ac^2
ac^2= bc^2-ab^2
ac^2= 16cm-25cm
ac^2=9cm
ac=3cm
bd=3cm (opp side of IIgm)
now,
ac^2+bd^2
3^2+3^2
9cm+9cm
18cm
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