Math, asked by lalitsarda1721, 9 months ago

ABCD is a parallelogram , AB = 5 cm , BC = 4 cm , then the value of AC^2 + BD^2 is

Answers

Answered by anjaneyuluyellampall
0

Answer:

AC =3,BD=3.

AC^2+BD^2=18

18 is the answer

Answered by vaishalihedaoohedaoo
0

Answer:

By pythagoras theorom,

bc^2= ab^2+ac^2

ac^2= bc^2-ab^2

ac^2= 16cm-25cm

ac^2=9cm

ac=3cm

bd=3cm (opp side of IIgm)

now,

ac^2+bd^2

3^2+3^2

9cm+9cm

18cm

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