Question

ABCD is a parallelogram AB = 7, BC = 8 and AC = 13 then distance between AB and CD is equal to:​

Answer 1

Answer:

20the length of ab and ad is 20

Answer 2

Answer:

Step-by-step explanation:

Given, AB=8cm;BC=4cm

Perpendicular distance between AB and BC is DL=3cm

The area of the parallelogram =base×height

                                                  =AB×DL

                                                  =8×3=24cm  

2

 

Area of the parallelogram =base×height

                                           =AD×BM

                                      24=4×height

                             Height=6cm

So the perpendicular distance between AD and BC is 6cm