ABCD is a parallelogram ab is divided at P and CD is divided at Q so that Ap:PB = 3 :2 and CQ:QD =4 : 1 if PQ intersect at ac at R then prove that AR = 3 /7AC
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hey......your answer:-
question:-
ABCD is a parallelogram. AB is divided at P and CD at Q such that AP : PB is 3 : 2 and CQ : QD is 4 : 1. if PQ meets AC at R, prove that AR= 3/7 AC ?
answer:-
Step-by-step explanation:
Let, AB = CD = 5x according to the parallelogram definition that opposite sides are equal.
AP=3x,PB=3x and CQ=4x,QD=x
ARP ~ CRQ
AP/CQ=AR/RC
3x/4x=AR/RC
AR/RC=3/4
so,AR=3 and RC=4
AR+RC=AC=7
hence, AR/AC=3/7
AND AR=3/7AC.....PROVED
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#hope it helps you ayesha#
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