Math, asked by ayesha7351, 10 months ago

ABCD is a parallelogram ab is divided at P and CD is divided at Q so that Ap:PB = 3 :2 and CQ:QD =4 : 1 if PQ intersect at ac at R then prove that AR = 3 /7AC​

Answers

Answered by Anonymous
9

hey......your answer:-

question:-

ABCD is a parallelogram. AB is divided at P and CD at Q such that AP : PB is 3 : 2 and CQ : QD is 4 : 1. if PQ meets AC at R, prove that AR= 3/7 AC ?

answer:-

Step-by-step explanation:

Let, AB = CD = 5x according to the parallelogram definition that opposite sides are equal.

AP=3x,PB=3x and CQ=4x,QD=x

ARP ~ CRQ

AP/CQ=AR/RC

3x/4x=AR/RC

AR/RC=3/4

so,AR=3 and RC=4

AR+RC=AC=7

hence, AR/AC=3/7

AND AR=3/7AC.....PROVED

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#hope it helps you ayesha#

Answered by Anonymous
3

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be brainly ✌️

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