Question

ABCD is a parallelogram. AC is its diagonal. prove that AC divides parallelogram ABCD into two concurrent triangles​

Answer 1

Step-by-step explanation:

this is a very long question not worth 5 points u need to give 10 points + for these type of questions

Answer 2

Answer:

Given: A parallelogram ABCD and AC is its diagonal .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have

∠DAC = ∠BCA [alt. int. angles, since AD | | BC]

AC = AC [common side]

and ∠BAC = ∠DAC [alt. int. angles, since AB | | DC]

∴ By ASA congruence axiom, we have

△ABC ≅ △CDA

so it divides the parallogram into 2 congruent parts