Question

abcd is a parallelogram
, AE I DC and CF I AD.

AD = 6 cm, CF = 10 cm, and AE = 8 cm, find AB​

Answer 1

Answer:

Area of llgm= b×h

= 6× 10 =60cmsq.

therefore area of llgm is also equal to DC×CF

60/8= DC

7.5cm= DC

as ABCD is a llgm

therefore the opposite sides of the llgm are equal

hence, DC= AB=7.5

Answer 2

Question :-

In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.

Answer :-

We have, AE ⊥ DC and AB = 16 cm

∵ AB = CD [Opposite sides of parallelogram]

∴ CD = 16 cm

Now, area of parallelogram ABCD = CD x AE

= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]

Since, CF ⊥ AD

∴ Area of parallelogram ABCD = AD x CF

⇒ AD x CF = 128 cm

⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]

⇒ AD = 128/10 cm = 12.8 cm 10

Thus, the required length of AD is 12.8 cm

Hope it helps ❤ Mrk as brainliest