ABCD is a parallelogram , AE is perpendicular to DC and CF is perpendicular to AD . if AB= 16cm , AE=8cm and CF= 10cm .find AD
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Hope this helps you
It is given that it is parallelogram
Here there are two triangle
So, area of parallelogram =base x height
DC x AE = AD x CF
16 x 8 =AD x 10
16 x 8 = AD x 10
128= AD x 10
128/10 =AD.
12.8 =AD
Area of parallelogram = base x height
It is given that it is parallelogram
Here there are two triangle
So, area of parallelogram =base x height
DC x AE = AD x CF
16 x 8 =AD x 10
16 x 8 = AD x 10
128= AD x 10
128/10 =AD.
12.8 =AD
Area of parallelogram = base x height
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bvijaysingh:
Thanks , it was very helpful
today my exams of 9th got over. I am in 10 from Monday
oh you are so lucky .
my maths exam is on monday
It is my last exam
All the best for your exam
thankxx
If you don't mind can I ask you a question
What is your name
vishwa
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Question :-
In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.
Answer :-
We have, AE ⊥ DC and AB = 16 cm
∵ AB = CD [Opposite sides of parallelogram]
∴ CD = 16 cm
Now, area of parallelogram ABCD = CD x AE
= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]
Since, CF ⊥ AD
∴ Area of parallelogram ABCD = AD x CF
⇒ AD x CF = 128 cm
⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]
⇒ AD = 128/10 cm = 12.8 cm 10
Thus, the required length of AD is 12.8 cm
Hope it helps ❤ Mrk as brainliest
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