Math, asked by sohadesai1304, 3 months ago

ABCD is a parallelogram. AE is the altitude from A to DC and AF is the altitude from A

to BC. If DC = 12 cm, AE = 5.6cm and BC is 14cm.

(a) Find the area of parallelogram ABCD. ​

Answers

Answered by debasmitakar2006
1

Answer:

In parallelogram ABCD, AD = 12.8 cm.

Solution:

Given:

AE = 8cm

AB = 16 cm

CF = 10 cm

In a parallelogram ABCD, “CD = AB = 16 cm” (∵Opposite sides of parallelogram are equal)

The value of AD can be found by multiplying base by height. Both base and height of parallelogram is perpendicular each other.

Area of parallelogram = \bold{b \times h}b×h

Area of ABCD = A E \times C D=A D \times C FAE×CD=AD×CF

\begin{gathered}\begin{array}{l}{16 \times 8=A D \times 10} \\ {128=A D \times 10}\end{array}\end{gathered}

16×8=AD×10

128=AD×10

AD = 12.8 cm.

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