ABCD is a parallelogram, AM ⊥EC, AB = 12 cm, EC = 20 cm and AM = 11 cm. Find the area of the quadrilateral ABCE.
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In parallelogram ABCD, we have given AB=10cm, AE=8cm, and CF=12cm.
⇒ AB=DC=10cm [Opposite sides of parallelogram are equal]
⇒ Lets find out area of parallelogram with height AE and base DC.
⇒ Area of parallelogram ABCD=b×h
⇒ Area of parallelogram ABCD=DC×AE
⇒ 10×8
∴ Area of parallelogram ABCD=80cm
2
--- ( 1 )
⇒ Now, to find area of parallelogram let CF be the height and AD will be base.
⇒ Area of parallelogram ABCD=CF×AD
⇒ 80=12×AD [From ( 1 )]
⇒ AD=
12
80
∴ AD=6.66cm
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