ABCD is a parallelogram and AE bisects
angle A. Prove that DE = BC.
A
B
D
E
С
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Since AE bisects angle DAB then angle DEA is congruent to angle DAE and that makes triangle DAE an equiangular triangle
Step-by-step explanation:
Since triangle DAE is equiangular, it also makes it equilateral. We know AD = BC because opposite sides of a parallelogram are equal and AD = DE because they are sides of an equilateral triangle.
Hence that makes BC = DE
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