Question

ABCD is a parallelogram and angleA=120°. If the bisector of angle A and angle B meet at point P show that angle APB is a right angle​

Answer 1

Answer:

∠APB is a right angle

Step-by-step explanation:

∠A = 120° and from property of parallelogram ∠A + ∠B = 180° . So ∠B =60°

angle bisector divides angle equally, So ∠PAB = 60° and ∠PBA = 30°  and the point P where both angle bisector meets makes a triangle

angle of triangle = 180°

∠PAB + ∠PBA + ∠APB = 180°

∠APB = 180° - 60° -30°

∠APB = 90°

Hence , ∠APB is a right angle