ABCD is a parallelogram and AP anf CQ are perpendicular from vertices A and C on diagonal BD. Show that:
1. Triangle APB is congruent with triangle CQD.
2. AP = CQ.
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Answered by
47
HEYA...
FRIEND....
=================================
HERE YOUR ANSWER YOUR.
QUESTION
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Given = ABCD is a parallelogram
To Prove = AP = CQ
Proof = Δ APB and Δ CQD
= ∠APB = ∠CQD
[ EACH RIGHT ANGLE ]
= AB = CD (opposite sides of parallelogram ABCD).
= ∠ABP = ∠CDQ (Alternate interior angles for AB||CD).
Δ APB is congruent to Δ CQD [ AAS ]
= AP = CQ [CPCT]
PROVED......
THANKYOU....
FRIEND....
=================================
HERE YOUR ANSWER YOUR.
QUESTION
=================================
Given = ABCD is a parallelogram
To Prove = AP = CQ
Proof = Δ APB and Δ CQD
= ∠APB = ∠CQD
[ EACH RIGHT ANGLE ]
= AB = CD (opposite sides of parallelogram ABCD).
= ∠ABP = ∠CDQ (Alternate interior angles for AB||CD).
Δ APB is congruent to Δ CQD [ AAS ]
= AP = CQ [CPCT]
PROVED......
THANKYOU....
Manik04s:
It was confusing me.
Answered by
23
Hey Friend!!!
Here's your answer in the attachment...
Hope this helps you...^_^
Here's your answer in the attachment...
Hope this helps you...^_^
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