Question

Abcd is a parallelogram and apq is a straight line meeting bc at p and dc produced at q prove that bp×dq=ab×bc

Answer 1

hey!!!
this is your answer
!!!!!
given,
ABCD is a parallelogram
to prove: BP × DQ = AB ×BC
proof:- in ∆ABP and ∆QDA
< B= <D ( opposite angles of parallelogram)
<BAP =< AQD ( alternative integer angle)
then, ∆ABP~ ∆QDA
So, AB/QD = BP/DA ( corresponding parts of similar triangle are proportion) But, DA= BC ( opposite side of parallelogram)
then,. AB/QD =BP/BC
or, AB×BC = QD ×BP
I hope it helpful for you

Answer 2

Answer:

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