ABCD is a parallelogram and BEC is a triangle . BFE and CDE are straight line . Angle BAF is 46 and BFA is 65 . Find angle BEC and EDA ?
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Step-by-step explanation:
∠BAD=∠CDF (Corresponding angles for parallel lines AB and CD)
∠BAD=∠CBE (Corresponding angles for parallel lines AB and CD)
Thus, ∠CDF=∠CBE (I)
We know, AD=BC (ABCD is a parallelogram)
and AD=DF (Given)
Thus, DF=BC (II)
Similarly, BE=CD (III)
Now, In △CDF and △CBE
∠CDF=∠CBE (From I)
FD=BC (From II)
BE=CD (From III)
Thus, △FDC≅△CBE (SAS rule)
△BEC≅△DCF
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