Question

ABCD is a parallelogram and BEFC is a square. Show that triangles ABE and DCF are congruent.​

Answer 1

Step-by-step explanation:

Given: ABCD is a parallelogram

BEFC is a square

To prove: ΔABE≅ΔDCF

Proof: In ΔABE and ΔDCF,

AB=DC (Opposite sides of a ║gm are equal)

∠AEB=∠DFC=90°(Each angle of a square is 90°)

Also, BE=CF (AD║BC, and dist. beween parallel lines remain constant)

So, ΔABE≅ΔDCF (by RHS congruence)

HENCE PROVED!