Question

Abcd is a parallelogram and befc is a square.show that triangles Abe and dcf are congruent

Answer 1

Given: ABCD is a parallelogram

BEFC is a square

To prove: ΔABE≅ΔDCF

Proof: In ΔABE and ΔDCF,

AB=DC (Opposite sides of a ║gm are equal)

∠AEB=∠DFC=90°(Each angle of a square is 90°)

Also, BE=CF (AD║BC, and dist. beween parallel lines remain constant)

So, ΔABE≅ΔDCF (by RHS congruence)

HENCE PROVED!

Answer 2

Answer:

here is your answer mate

Step-by-step explanation:

In the parallelogram ABCD,

                BA = CD.

In the square BEFC,

                EB = FC.

Since EB is parallel to FC and BA is parallel to CD then,