ABCD is a parallelogram and E is a point on BC. if the diagonal BD intersects AE at F , prove that AF x FB = EF x FD.
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Hlw mate!!
We have:
AFD = EFB .
(vertically opposite angles )
Therefore,DA F=BEF
(Alternanate angels)
DAF ~ ∆ BEF
(AA similarity theorem )
=AF/BF =FD/FB
Or AF ×FB = FD× EF
This completes the proof.
Hope it helpful
We have:
AFD = EFB .
(vertically opposite angles )
Therefore,DA F=BEF
(Alternanate angels)
DAF ~ ∆ BEF
(AA similarity theorem )
=AF/BF =FD/FB
Or AF ×FB = FD× EF
This completes the proof.
Hope it helpful
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