ABCD is a parallelogram and E is middle point of side AD.EC meets BD in O. If area of parallelogram is 24unit then area of ∆EOD Is equal to? Please ansr me fast.
JinKazama1:
wait let me check once again
Wait It is 2 units
yes!!i also have doubts in 2 and 3
which method you used?
i don't know!!bcz ...its a objective type questions..and.. someone told me so
I will answer soon
Answer is 2units, I am sure now.
ok!!. i am waiting..
Answers
Answered by
30
Final Answer : 2units
Understanding :
1) Vector Method.
Steps:
1) Let A be (a) vector.
D be (0) vector. zero vector
C be (b) vector
=> In parallelogram ABCD, B is (a + b) vector.
2) Let the point O divides EC and DB vector in the ratio 1:t and lambda : 1 respectively.
Then, use section formula of vectors.
3)equate both similar points of O vector.
4) We know that,
|a x b| = 24units
5) Area of Triangle EOD =1/2 (OE x OD)
Use this to get area.
For Calculation see pic
Understanding :
1) Vector Method.
Steps:
1) Let A be (a) vector.
D be (0) vector. zero vector
C be (b) vector
=> In parallelogram ABCD, B is (a + b) vector.
2) Let the point O divides EC and DB vector in the ratio 1:t and lambda : 1 respectively.
Then, use section formula of vectors.
3)equate both similar points of O vector.
4) We know that,
|a x b| = 24units
5) Area of Triangle EOD =1/2 (OE x OD)
Use this to get area.
For Calculation see pic
Attachments:
great....!!!!...i ... thank yoy so much .....
i was trying to find answers....for a long Time
My Pleasure. Hope You understand my answer
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Answered by
6
Answer:
Step-by-step explanation:
ou can get something interesting from the above, Can’t you?
Don’t worry, I will explain. If you observe closely.
angleDAF=angleEBF
Because its a parallelogram
So DAF and EBF are similar triangles.
Considering similar triangle theorem.
DA / AF = EB/BF
If you want to know about similar triangle theorem
Theorems about Similar Triangles
DA = BC =2 EB ( as E is mid point of BC)
2EB / AF = EB / BF,
So after re arranging AF = 2 BF
Hope you got the solution.
All the best!
:)
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