Question

abcd is a parallelogram and e is midpoint of bc. if de and ab when produced meet at f prove that ae=2af.plzz provide the full solution..

Answer 1

Mistake in the question!
Question will be this:
Abcd is a parallelogram and e is midpoint of bc. if de and ab when produced meet at f prove that af=2ab

We know,
E is midpoint of BC.
∴BC = CE
Let consider triangles ΔCDE and ΔBEF
So,
∠CED = ∠BEF (vertically opp. angle)
∠DCE = ∠FBE (alternate angles)
So.....ΔCDE ≈  ΔBFE
Then CD = BF (CPCT)
∵CD = AB
∴AB = BF
→AF = AB + BF
→AF = AB + AB
→AF = 2AB
It is proved that AF = 2AB

Answer 2

The answer is in the picture.


Hope it helps.