Question

ABCD is a parallelogram and E is the mid point of side BC. If DE and AB when produced meet at F, prove that AF= 2A ​

Answer 1

Answer:

Step-by-step explanation:

in the figure

△DCE and BFE

any DEC = any BEF (vertically opp any)

EC=BE (E is the mid point)

∠DCB=∠EBF (alternate angle DC parallel to AF)

So △DCE congruent to △BFE

Therefore DC=BF ...(1)

now CD = AB (ABCD is a parallelogram)

soAF=AB+BF

=AB+DC from (1)

=AB+AB

=2AB

Answer 2

Answer:

ABCD and ∆ADF are on same base and between same parallels so there area are equal .

so by the congruent rule we can say that AF =2A