Question

ABCD is a parallelogram and E is the
midpoint of BC . The side DC
is extended such that it meets AE, when
extended, at F. Prove that DF = 2DC

please answer the questions as soon as possible it's urgent
​

Answer 1

Answer:

ABCD is a parallelogram and E is the midpoint of BC, such that if AB and it is extended they meet at point F.

In ΔBAE and ΔEFC

Since, AD // BC (sides of parallelogram)

DAB and EBF are interior alternate angles.

Vertically opposite angles.

Since, E is the midpoint, it divides BC into equal parts.

by AAS property.

So, by C. P. C. T. C  

Now,

Since,

CF = AB (As proved above)

AB = DC (Opposite sides of parallelogram)

So,

Step-by-step explanation:

Answer 2

Answer:

mark me as brainest I will promise to answer this question