Question

ABCD is a parallelogram and line segments AX, CY bisects angle A and angle C respectively. Show that AX ||CY.

Answer 1

Here, ABCD is a //gm.
In, ∆DXA&CYB
DX=BY(opp.sides of //gm.and also parallel)
DA=CB(". ")
angle D= angle B(opp.sides of //gm.)
therefore,∆DXA≈∆CYB
AX=CY(C.P.C.T)
now, XA=CY then, XA//CY

Answer 2

First of all...
The Above answer is wrong ....
Now the correct answer is ......
in the pic
HOPE IT HELPS....