abcd is a parallelogram and o is a point in its interior. prove that area of triangle aob +area of triangle cod =area of triangle aod +area of triangle boc.
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Answered by
18
Area of Triangle AOB is congruent to area of triangle AOD by SSS rule because AB=AD (Opp sides of parallelogram)
AO=BO=DO (diagonals are equal and bisected each other)so AO=AO
BO=DO
Similarly triangle COD will be equal to triangle BOC (by sss rule again)
Since triangles AOB=AOD =COD=BOC
so proved
AO=BO=DO (diagonals are equal and bisected each other)so AO=AO
BO=DO
Similarly triangle COD will be equal to triangle BOC (by sss rule again)
Since triangles AOB=AOD =COD=BOC
so proved
Answered by
4
Answer:
Step-by-step explanation:
Area of Triangle AOB is congruent to area of triangle AOD by SSS rule because AB=AD (Opp sides of parallelogram)
AO=BO=DO (diagonals are equal and bisected each other)so AO=AO
BO=DO
Similarly triangle COD will be equal to triangle BOC (by sss rule again)
Since triangles AOB=AOD =COD=BOC
so proved
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