Abcd is a parallelogram and p is any point on the side ad .If the area of the parallelogram is 70cm square ,then find the area of triangle pbc
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We know that a triangle will have half the area of parallelogram if parallelogram and triangle lie on same base and between same parallels
Here triangle PBC and parallelogram ABCD lie on same base BC and between same parallels AD
Therefore 1/2ar of ABCD=ar of PBC which implies,are of triangle=70/2
=45cm^2
Here is the diagram for you
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We know,
In ||gm ABCD,
ar(∆pbc)=1/2 ar(||gm abcd)
{Same base,BC and b/w the same parallels AD and BC}
Thus,
ar(∆pbc)=70×1/2
=35°
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