Question

ABCD Is a parallelogram and Q is any point on side AD. if ar.(tri.QBC)=10 sq.cm.find ar (tri.QAB)+ar(tri.QDC)

Answer 1

ar(tri.QBC)=1/2 ar(//gm.ABCD)

ar(tri.QBC)+ar(tri.QAB)=ar(//gm.ABCD)

ar(//gm.ABCD)=2×ar(tri.QBC)

ar(tri.QAB+tri.QDC)=2×10

=20sq.cm.

Answer 2

Answer:

ar(∆QAB) +ar(∆QDC)= (∆QBC)

5 + 5 = 10