Question

ABCD Is a parallelogram and Q is any point on side AD. if ar.(tri.QBC)=10 sq.cm.find ar (tri.QAB)+ar(tri.QDC)​

Answer 1

Step-by-step explanation:

use this formula this formula is area of parallelogram and get your answer

Answer 2

1.ar (ot) BC) = 1/2 av ( 11ABCD)

2.ar \ //ABCD) = 10X2 =20

ar (BQDL) + ar(∆QBC) +ar(& A&B) = 20

°•° ar (∆QDC)=10ar (∆AQB) (by symmetry)

ar (∆QDC) = 20-10/2=5