Question

ABCD is a parallelogram and so and Cq perpendicular from vertical a and c in diagonal Cx show that triangle apb = cqb and ap=iq​

Answer 1

Answer:

In △APB and △CQD,

∠APB=∠CQD (Each 90

∘

)

AB=CD (Opposite sides of parallelogram ABCD)

∠ABP=∠CDQ (Alternate interior angles for AB∥CD)

∴△APB≅△CQD (By AAS congruency)

∴AP=CQ by CPCT

Hence proved.

Explanation:

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Answer 2

Answer:

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