Abcd is a parallelogram and t is the mid point of ad. If at of quadrilateral abct = 45 sq units , then find area of triangle tcd.
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ABCD is a parallelogram, with the base as AD (for example).
T is midpoint of AD.
Let E be the midpoint of BC. Join TE and TC.
Let the Area of ΔCTD = x sq units.
We know that TECD is also a parallelogram with area = 1/2 of ABCD.
Ar(TECD) = ΔTEC + ΔTCD = 2 * Δ TCD (In this parallelogram, TC is the diagonal. So the area of both triangles is the same).
Hence Ar(ABCD) = 4 * ΔTCD
Also Ar(quadrilateral ABCT) = 45 sq units
Ar(ABCT) + ΔTEC = 3 * ΔTCD
ΔTCD = 15 sq units.
T is midpoint of AD.
Let E be the midpoint of BC. Join TE and TC.
Let the Area of ΔCTD = x sq units.
We know that TECD is also a parallelogram with area = 1/2 of ABCD.
Ar(TECD) = ΔTEC + ΔTCD = 2 * Δ TCD (In this parallelogram, TC is the diagonal. So the area of both triangles is the same).
Hence Ar(ABCD) = 4 * ΔTCD
Also Ar(quadrilateral ABCT) = 45 sq units
Ar(ABCT) + ΔTEC = 3 * ΔTCD
ΔTCD = 15 sq units.
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