Question

ABCD is a parallelogram and T is the midpoint of AD. If ar(quadrilateral ABCT)=45cm,then find at(∆ACD).

Answer 1

area of trapezoid is A=(a+b)/2×H
AND WE KNOW THAT aDCT IS A TRAPEZIOS AS IT HAS TWO PARALLEL LINES SO a=Y/2 ,b=Y if we solve the equation we will get  H=60/Y AND THE AREA OF ACD =1/2×Y×60/Y THAT IS EQUAL TO 30

Answer 2

area of trapezoid is A=(a+b)/2×HAND WE KNOW THAT aDCT IS A TRAPEZIOS AS IT HAS TWO PARALLEL LINES SO a=Y/2 ,b=Y if we solve the equation we will get  H=60/Y AND THE AREA OF ACD =1/2×Y×60/Y THAT IS EQUAL TO 30