Abcd is a parallelogram and x is the mid-point of AB. If ar(triangle adc) = 24 cm2 , then find ar(axcd)
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24+ ar of and
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MYNAME098:
Sry ar of axd
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[ADCX]=[ADC]+[AXC]=[ADC]+[ABC]/2
SINCE [ABC]=[ADC] IT IS EQUAL TO 24 CM^2
THEREFORE, [AXC]=24/2=12CM^2
AND, [ADCX]=24+12 CM^2= 36 CM^2
SINCE [ABC]=[ADC] IT IS EQUAL TO 24 CM^2
THEREFORE, [AXC]=24/2=12CM^2
AND, [ADCX]=24+12 CM^2= 36 CM^2
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