Question

Abcd is a parallelogram and x is the midpoint of bc the line ax produced meet dc produced at q the Parallelogram aqbp is complete prove that triangle abx is congruent to triangle qcx and dc=cq=qp

Answer 1

Answer:

Step-by-step explanation:

In triangle BCP, X is the mid point of line BC and XQ is parallel to PB so Q is the mid point of line CP.

=> CQ = PQ

​Also PQ = AB, so CQ = AB

angle XCQ = angle XBA (AIA)

angle XQC = angle XAB (AIA)

So in triangle QCX and triangle ABX

angle XCQ = angle XBA (AIA)

CQ = AB

angle XQC = angle XAB (AIA)

So by ASA congruency rule triangle ABX is congruent to triangle QCX

​AB = CD and AB = PQ (by 2 //gms)

so CD = PQ.

Hope it is helpful ........

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Answer 2

Answer:

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