Question

ABCD is a parallelogram,angle A=3x-5° and angle B=9x+5°,then x=?​

Answer 1

Given:-

• ∠A of parallelogram ABCD is 3x - 5°.
• ∠B of parallelogram ABCD is 9x + 5°.

To find:-

• Value of x.

Solution:-

We know that,

Sum of two adjacent angles of parallelogram is 180°.

So,

➝ ∠A + ∠B = 180°

➝ (3x - 5°) + (9x + 5°) = 180°

➝ 3x - 5° + 9x + 5° = 180°

➝ 12x -5 + 5 = 180°

➝ 12x = 180°

➝ x = 180°/12

➝ x = 15°

Verification:-

➝ ∠A + ∠B = 180°

➝ (3x - 5°) + (9x + 5°) = 180°

• Put x = 15°

➝ (3×15° - 5°) + (9×15° + 5°) = 180°

➝ 45° - 5° + 135° + 5° = 180°

➝ 40° + 140° = 180°

➝ 180° = 180°

Hence, Verified.

Therefore,

Value of x is 15°.

Answer 2

ANSWER:

IN A PARALLELOGRAM ABCD ARE THE VERTEX

ANGLE A = 3X- 5

ANGLE B= 9X +5

ANGLE A + ANGLE B = 180 ( SUM OF TWO CO-

INTERIOR ANGLES)

(3X-5) + (9X+5) =180

3X-5 + 9X+ 5 = 180

12X = 180

X = 180/ 12

x = 15

ANGLE A = 40 °

ANGLE B = 140°

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