ABCD is a parallelogram BE is the height from B to DC and BF is the height from B to AD. if DC=12cm and BE=7.6cm.find (1)=Area of a parallelogram ABCD. (2)=BF,if AD=8cm.
Answers
Answer:
The area of the parallelogram ABCD is and the length of the height BF is 11.4 cm.
Step-by-step explanation:
1) It is given that the length DC = 12 cm. Then, base AB = DC =12 cm. And height, h = BE = 7.6 cm.
The area of a parallelogram is the product of the base and height. That is,
Therefore, the area of the parallelogram,
Hence the area of the parallelogram ABCD is
2) Considering the side AD as the base with height BF, the area is given as,
Hence the length of the height BF is 11.4 cm.
here is your answer
Step-by-step explanation:
The area of the parallelogram ABCD is 91.2\ cm^{2}91.2 cm
2
and the length of the height BF is 11.4 cm.
Step-by-step explanation:
1) It is given that the length DC = 12 cm. Then, base AB = DC =12 cm. And height, h = BE = 7.6 cm.
The area of a parallelogram is the product of the base and height. That is,
A=bhA=bh
Therefore, the area of the parallelogram,
\begin{gathered}A=12\times7.6\\\\A=91.2\ cm^{2}\end{gathered}
A=12×7.6
A=91.2 cm
2
Hence the area of the parallelogram ABCD is 91.2\ cm^{2}91.2 cm
2
2) Considering the side AD as the base with height BF, the area is given as,
\begin{gathered}AD\times BF=91.2\\\\8\times BF=91.2\\\\BF=\dfrac{91.2}{8} \\\\BF=11.4\ cm\end{gathered}
AD×BF=91.2
8×BF=91.2
BF=
8
91.2
BF=11.4 cm
Hence the length of the height BF is 11.4 cm.