Math, asked by ferozpurwale, 4 days ago

ABCD is a parallelogram BE is the height from B to DC and BF is the height from B to AD. if DC=12cm and BE=7.6cm.find (1)=Area of a parallelogram ABCD. (2)=BF,if AD=8cm.​

Answers

Answered by shabeehajabin
1

Answer:

The area of the parallelogram ABCD is 91.2\ cm^{2} and the length of the height BF is 11.4 cm.

Step-by-step explanation:

1)   It is given that the length DC = 12 cm. Then, base AB = DC =12 cm. And height, h = BE = 7.6 cm.

The area of a parallelogram is the product of the base and height. That is,  

             A=bh

Therefore, the area of the parallelogram,

                                             A=12\times7.6\\\\A=91.2\ cm^{2}

Hence the area of the parallelogram ABCD is 91.2\ cm^{2}

2)  Considering the side AD as the base with height BF, the area is given as,

           AD\times BF=91.2\\\\8\times BF=91.2\\\\BF=\dfrac{91.2}{8} \\\\BF=11.4\ cm

Hence the length of the height BF is 11.4 cm.

Attachments:
Answered by avman08
1

here is your answer

Step-by-step explanation:

The area of the parallelogram ABCD is 91.2\ cm^{2}91.2 cm

2

and the length of the height BF is 11.4 cm.

Step-by-step explanation:

1) It is given that the length DC = 12 cm. Then, base AB = DC =12 cm. And height, h = BE = 7.6 cm.

The area of a parallelogram is the product of the base and height. That is,

A=bhA=bh

Therefore, the area of the parallelogram,

\begin{gathered}A=12\times7.6\\\\A=91.2\ cm^{2}\end{gathered}

A=12×7.6

A=91.2 cm

2

Hence the area of the parallelogram ABCD is 91.2\ cm^{2}91.2 cm

2

2) Considering the side AD as the base with height BF, the area is given as,

\begin{gathered}AD\times BF=91.2\\\\8\times BF=91.2\\\\BF=\dfrac{91.2}{8} \\\\BF=11.4\ cm\end{gathered}

AD×BF=91.2

8×BF=91.2

BF=

8

91.2

BF=11.4 cm

Hence the length of the height BF is 11.4 cm.

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