ABCD is a parallelogram CDEF and ADGH are two squares on sides DC and AD of the
parallelogram respectively Prove that EG=BD.
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According to the question:
DC=DE (sides of same square)
AD=GD (SIDES OF THE SAME SQUARE)
so, in the same way,
AD^2 +DC^2= GD^2 + DE^2= BD^2= EG^2
Hence, BD=EG .
HOPE YOU UNDERSTAND IT
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