Question

ABCD is a parallelogram. DQ is the angle bisector of <D meeting AB at P and CB produced to Q. Show that <APD= <PQB.​

Answer 1

Step-by-step explanation:

In Tri. ADP and Tri. CDQ

< A = < C ( opposite angles of parallelogram )

< CDQ = < ADP ( bisected angle)

Tri. ADP is similar to triangle CDQ ( by Angle Angle)

Then < APD = < PQB

Mark be brainliest