Question

ABCD is a parallelogram. E and Fare the mid-points of the sides
AB and CD respectively. Prove that the line segments AF and CE trisect (divide into three
equal parts) the diagonal BD.
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Answer 1

Step-by-step explanation:

Given = ABCD is a parallelogram where E&F are mid point of side Ab and CD respectively.

To prove = Af&EC trisect BD

prove= AB|| CD {opposite side of a parallelogram

AE||CF {parts of parallels line}

AB=CD {opposite sides of a parallelogram}

½AB ½ CD

AE=CF {f is the mid point of CD}