Question

ABCD is a parallelogram. E is on ray AD such that A-D-E
and AD = DE. BE intersect CD at F. If (DEF] = 5.
Find area of ||gm ABCD​

Answer 1

Answer:

Step-by-step explanation: We can proceed to prove that this parallelogram is indeed a rhombus, using the fact that if a parallelogram's diagonals are perpendicular, it is a rhombus – and we've shown above that these diagonals are indeed perpendicular. So the areas of the parallelogram is (diagonal x diagonal /2 ), or 24×10/2=120, as above. In a quadrilateral ABCD, if one pair of opposite sides is equal and parallel, then it is a parallelogram.

Parallelogram

Solve for area

A=bh

b Base

h Height