Question

ABCD is a parallelogram. EDC is a straight line. F is the point on AD so that BFE is a straight line. Angle EFD = 35° Angle DCB = 75° Show that angle ABF = 70° Give a reason for each stage of your working

Answer 1

Step-by-step explanation:

Angle DFE = AFB = 35° ( Opposite angles)

Angle ECB = BAF = 75° (Opposite angles of parallelogram )

in ∆AFB

Two angles are 35° and 75° . Since Sum of angles be 180° . So third angle

ABF = 180°- (75°+35°) = 70°

Answer 2

Answer:

Angle DFE = AFB = 35° ( Opposite angles)

Angle ECB = BAF = 75° (Opposite angles of parallelogram )

in ∆AFB

Two angles are 35° and 75° . Since Sum of angles be 180° . So third angle

ABF = 180°- (75°+35°) = 7

PLEASE FOLLOW ME