ABCD is a parallelogram field with ΔA=60.if there are two fire stations at points c and d and fire is reported at point o,then which fire station has to send their team to catch the fire first ?why?
nope:
where is o
db and ac intersect each other and o is the centre of them
a is area
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Probably some details are missing like the length of CD or AB or BC... Area is given, we needed to know the angles.
In a parallelogram the adjacent angles are supplementary ie., sum is 180 deg.
angle C + angle D = 180.
If angle C > angle D, then OC < OD, So the fire station at C is nearer to the fire at O. So choose the firestation at the obtuse angle rather than at the acute angle.
If angle D = angle C, then OC = OD. Then both stations are equi-distant.
In a parallelogram the adjacent angles are supplementary ie., sum is 180 deg.
angle C + angle D = 180.
If angle C > angle D, then OC < OD, So the fire station at C is nearer to the fire at O. So choose the firestation at the obtuse angle rather than at the acute angle.
If angle D = angle C, then OC = OD. Then both stations are equi-distant.
Answered by
1
Probably some details are missing like the length of CD or AB or BC... Area is given, we needed to know the angles.
In a parallelogram the adjacent angles are supplementary ie., sum is 180 deg.
angle C + angle D = 180.
If angle C > angle D, then OC < OD, So the fire station at C is nearer to the fire at O. So choose the firestation at the obtuse angle rather than at the acute angle.
If angle D = angle C, then OC = OD. Then both stations are equi-distant.
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