Question

ABCD is a parallelogram find 1) < ABO
2)<ODC 3)<ACB 4)<CBD​

Answer 1

Answer:

∠ABO=

∠ODC=

∠ACB=

∠CBD=

Step-by-step explanation:

∠AOB=65° [V.O.A]

In ΔAOB,

∠OAB+∠ABO+∠AOB=180°[A.S.P]

35°+∠ABO+65°=180°

100°+∠ABO=180°

        ∠ABO=80°

∠C=35°[Alternate Angles]

In ΔODC,

65°+35°+∠ODC=180°[A.S.P]

              ∠ODC=80°